Question

What are the intercepts of the line

Answer 1

`y-intercept(0,-32)\\\\x-intercept((16)/(5),0)`

Explanation:

The y-intercept happens where x is 0, and the x-intercept if where y is 0. You can use this knowledge to find the intercepts.

This equation is written in slope-intercept form:

`y=mx+b`

where b is the y-intercept, so the y-intercept is -32.

To find the x intercept, insert 0 as the value of y:

`0=10x-32`

Solve for x. Add 32 to both sides:

`0+32=10x-32+32\\\\32=10x`

Divide both sides by 10:

`(32)/(10)=(10x)/(10) \\\\x=(32)/(10) =(16)/(5)`

The x-intercept is at
`(16)/(5)` or
`3.2` .

Find the points:

`y-intercept(0,-32)\\x-intercept((16)/(5),0)`

Finito.

Answer 2

y intercept (0,-32)

x intercept (3.2,0)

Explanation:

To find the y intercept set x = 0 and solve for y

y = 10x -32

y = 0-32

y = -32

(0,-32)

To find the x intercept set y = 0 and solve for x

y = 10x -32

0 = 10x -32

Add 32 to each side

32 = 10x

Divide by 10

32/10 = x

(3.2,0)