Question

If the molar heat of fusion of water is 6.01

kJ

mol

, how much heat energy was required to melt 2 kg of ice?

Answer 1

Answer : The heat energy required to melt 2 kg of ice was, 667.7 kJ

Explanation :

First we have to calculate the moles of ice.

`\text{Moles of ice}=\frac{\text{Given mass ice}}{\text{Molar mass ice}}=(2kg)/(18g/mol)=(2000g)/(18g/mol)=111.1mol`

Now we have to calculate the heat energy.

As, heat energy required to melt 1 mole of ice = 6.01 kJ

So, heat energy required to melt 111.1 mole of ice = 111.1 × 6.01 kJ

= 667.7 kJ

Therefore, the heat energy required to melt 2 kg of ice was, 667.7 kJ