Question

How many grams are there in 5.0 L of chlorine gas at STP?

Answer 1

15.85 grams

Step-by-step explanation:

Here we want to get the number of grams present in 5 litres of chlorine gas at STP

At STP, 1 mole of gas occupies a volume 22.4 dm³

X moles will occupy 5L (litres)

Thus we have that :-

`x * 22.4 = 5 * 1`

`→x = (5)/(22.4)`

`→x = 0.2232 \: moles`

Mathematically, the number of grams is the product of the number of moles and molar mass.

Molar mass of chlorine gas is 71 g/mol

So,

Mass = Mole × Molar mass

→ 0.2232 × 71

→ 15.85 g

Answer 2

1nmole of any ideal gas occupies 22.72 L