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What are the first 5 terms of the sequence generated by the formula an= 2(n!)

1 Answer

5 votes

Answer:

2, 4, 12, 48, 240

Explanation:

We have the recursive formula a_n = 2*(n!)

Find:

a_1 = 2* 1! = 2

a_2 = 2*(2!) = 4

a_3 = 2*(3!) = 2*6 = 12

a_4 = 2*(4!) = 2*24 = 48

a_5 = 2*(5!) = 2*5*24 = 240

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