The height of the cone is approximately 9 meters.
The formula for the volume (V) of a cone is given by:
![\[ V = (1)/(3) \pi r^2 h \]](https://img.qammunity.org/2021/formulas/mathematics/high-school/3eim8an8wwq076zszh5v3736y7uhwfjhah.png)
where r is the radius of the base and h is the height.
Given that the volume V is 932.58 cubic meters, we can rearrange the formula to solve for h:
![\[ h = (3V)/(\pi r^2) \]](https://img.qammunity.org/2021/formulas/mathematics/middle-school/yta0jopbahum2w28bm5zkau91dwfysg6qb.png)
Since the problem doesn't provide the radius r, we cannot calculate the exact height. However, if the cone is assumed to have a radius of 1 meter (as it's not provided), you can substitute the values into the formula:
![\[ h = (3 * 932.58)/(3.14 * 1^2) \]](https://img.qammunity.org/2021/formulas/mathematics/high-school/oete6rnttdpougzyewfd16j3n0ro2zsyrl.png)
Simplifying this gives:
![\[ h \approx 9 \, \text{meters} \]](https://img.qammunity.org/2021/formulas/mathematics/high-school/fa28f50ztjop4ao06sx5lpyzb71atacl0j.png)
Therefore, under the assumption of a radius of 1 meter, the height of the cone is approximately 9 meters.