Question

what is the molarity of a solution prepared by dissolving 15.0g of sodium hydroxide in enough water to make a total of 225 ml of solution​

Answer 1

1.6666 g/mol = 1
`(2)/(3)` g/mol

Step-by-step explanation:

Molar mass of NaOH= 23+16+1 =40g/mol

Mols in 15g = 15/40 mol

If this was dissolved in 225ml of water molarity of the solution is

`(15)/(40)` ÷ 225 x 1000 = 1.6666 g/mol = 1
`(2)/(3)` g/mol