2 Answers

Diah · Answer 1 · 2021-04-15T11:45:58+0000

Answer:

The final temperature of the ice is
$-40^(\circ)\ C$ .

Step-by-step explanation:

It is given that,

Energy, Q = 10 cal

Mass of ice, m = 2 g

Initial temperature,
$T_1=-30^(\circ)\ C$

We need to find the final temperature of the ice. We know that the specific heat of ice is
$0.5\ cal\ g^(-1) ^(\circ) C^(-1)$

The heat added in terms of specific heat is given by :

Q=mc(T_1-T_2)

T_2 final temperature of the ice

c is specific heat of ice

$T_2=T_1-(Q)/(mc)\\\\T_2=(-30)-(10)/(2* 0.5)\\\\T_2=-40^(\circ)$

So, the final temperature of the ice is
$-40^(\circ)\ C$ .

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