Question

A box contains about 5.54 1021 hydrogen

atoms at room temperature 21°C.
Find the thermal energy of these atoms.
Answer in units of J.

Answer 1

Answer:
`E=33.71\ J`

Step-by-step explanation:

Given

No of atoms of hydrogen
`N=5.54* 10^(21)`

Temperature of room
`T=21^(\circ)\approx 294\ K`

Thermal energy of the atoms is given by

`E=(3)/(2)NkT`

where k=boltzmann constant

`E=(3)/(2)* 5.54* 10^(21)* 1.38* 10^(-23)* 294`

`E=33.71\ J`

Hence the energy of the atoms is
`33.71\ J`