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Given CS = 3, SB = 6, CR = 4, and RA = x. What must the value of x be in order to prove SR II BA? Justify your answer. UPLOAT
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Given CS = 3, SB = 6, CR = 4, and RA = x. What must the value of x be in order to prove SR II BA? Justify your answer.

UPLOAT

User Kissiel
by
4.8k points

2 Answers

4 votes

Answer:

Just cross muiltiply

Explanation:

3 4

- - = 8 (POP Theorem)

6 x

Converse of Theorem 5-6: If a line divides two sides of a triangle proportionally, it is parallel to the third side.

You're welcome Ody$$eyware

User Alan Judi
by
5.0k points
4 votes

Answer:

4, because CR and RA are the same length

User Max Bates
by
5.1k points
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