Question

How many moles of water can be produced with 4.3 moles of H2 and 5.6 moles of O2? Which reactant is limiting ? How many moles of the excess will be left after the reaction?​

Answer 1

4.3 Moles of Water

3.45 moles of O2 is excess.

Step-by-step explanation:

`2H_(2) + O_(2) -> 2H_(2)O`

2Moles of H2 produce 2Moles of Water

Required O2 moles 4.3/2 = 2.15 moles.

5.6 - 2.15 = 3.45 moles of O2 is excess.