Question

An external force of 5N is applied to a go-kart that is opposite it’s direction of travel for 5 seconds. What is the resulting momentum of the go-kart?

Options:

A: 25 kg m/s

B: 100 kg m/s

C: 975 kg m/s

Answer 1

25N.s=25kgm/s

Step-by-step explanation:

The resulting momentum in this case is equal to the impulse created by the force 5N during 5 seconds

ΔP=Force.time=F.t

= 5x5=25kgm/s