Answer:
See explaination
Step-by-step explanation:
We are given that : In 2015, the ethnic category including Del Taco, El Pollo Loco, Fazoli's, Panda Express, Taco Bell, and Taco John's had the fewest inaccuracies, with only 42 of 457 orders classified as inaccurate.
Thus x = number of orders that are filled accurately in the ethnic fast?food category = 457 - 42 = 415
Thus sample proportion of orders are filled accurately in the ethnic fast?food category is :
\hat{p}=\frac{x}{n}
\hat{p}=\frac{415}{457}
\hat{p}=0.9081
Also we have to find 95% confidence interval for the population proportion of orders that are filled accurately in the ethnic fast?food category.
Formula:
( \hat{p} - E \: \: ,\: \: \hat{p} + E )
where
E = Z_{c}\times \sqrt{\frac{\hat{p}\times (1-\hat{p})}{n}}
find Zc value for c =95% confidence level.
Find Area = ( 1 + c) / 2 = ( 1 + 0.95) / 2 = 1.95/2 = 0.9750
Look in z table for area = 0.9750 or its closest area and find corresponding z value.
See attached file for z table
Thus Zc = 1.96
E = Z_{c}\times \sqrt{\frac{\hat{p}\times (1-\hat{p})}{n}}
E = 1.96 \times \sqrt{\frac{0.9081 \times (1-0.9081 )}{457}}
E = 1.96 \times \sqrt{\frac{0.9081 \times 0.0919 }{457}}
E = 1.96 \times \sqrt{0.000183 }
E = 1.96 \times 0.013514
E =0.026487
E =0.0265
Thus we get :
( \hat{p} - E \: \: ,\: \: \hat{p} + E )
( 0.9081 - 0.0265 \: \: ,\: \: 0.9081 + 0.0265 )
( 0.8816 \: \: ,\: \: \: 0.9346 )
Thus a 95% confidence interval for the population proportion of orders that are filled accurately in the ethnic fast?food category is in between ( 0.8816 \: \: ,\: \: \: 0.9346 ) .