Question

What volume of a 2.60 M HCl solution should you use to prepare 2.80 L of a 0.200 M HCl solution

Answer 1

0.215 L HCl

Step-by-step explanation:

Using the relationship (M1 x V1 = M2 x V2) between Molarity (M) and Volume (v or L), we can find the volume of the 2nd volume amount.

First we rearrange our relationship equation to:
`V_2 = (M_1 * V_1 )/(M_2)`

Now, plug in the values.
`V_2 = (0.2 * 2.8)/(2.6)`

Calculating these values, we end up with the answer:

0.215 L HCl