Question

27. 2392 Two identical charged particles are 3.8 cm apart from each other and particle 1 exerts a force of 5x10-9 N on particle 2. Part Description Answer Save Status A. What is the charge on each particle? (include units with answer) 4.011*10^-22 C Format Check OK - using first value as 4.010e-13 nC Click here to check your answer 3.5 pts.88% 13% try penalty 8 try limit # tries: 1

Answer 1

The charge on each particle is
`q =2.832 *10^(-11) C`

Step-by-step explanation:

From he question we are told that

The distance of separation between particles is
`d = 3.8 cm = 0.038m`

The force exerted by on of the charged particle on the other charge particles is
`F = 5 *10^(-9)`

Generally the between these charge particle can be mathematically represented as

`F = (k q_1 q_2 )/(d^2)`

Where k is the colombe constant with a value of
`k = 9*10^9\ kg \dot m^3 \cdot s^(-4) A^(-2)`

Since the charge are identical

`q_1 = q_2 = q`

So the equation becomes

`F = (k q^2 )/(d^2)`

Making q the subject of the formula

`q =\sqrt{ (F * d^2 )/(k)}`

Substituting values

`q =\sqrt{ (5*10^(- 9) * 0.038^2 )/(9*10^9)}`

`q =2.832 *10^(-11) C`