Question

What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form?

Quadratic formula: x = -bb2 - 400
O x= 51075
O x= -5+2015
© x==335
© x= 5tys

Answer 1

Explanation:

`x = \frac{ - b + - \sqrt{ {b}^(2) - 4ac } }{2a} \\ x = \frac{ - 5 + - \sqrt{ {5}^(2) - 4(5) } }{2} \\ x = ( - 5 + - √(25 - 20) )/(2) \\ x = ( - 5 + - √(5) )/(2)`

Therefore, the zeroes would be:

`x1 = ( - 5 + √(5) )/(2) \\ x2 = ( - 5 - √(5) )/(2)`