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Find the equation of the line passing through the points (3,3) and (4,5)

User Eos
by
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1 Answer

3 votes

Answer:

y = 2x-3

Explanation:

First we find the slope

m = (y2-y1)/(x2-x1)

= (5-3)/(4-3)

2/1

The slope is 2

The slope intercept form of the equation is

y =m x+b where m is the slope and b is the y intercept

y = 2x+b

Substitute a point into the equation

3 = 2(3) +b

3 = 6+b

Subtract 6 from each side

3-6 =b

b = -3

y = 2x-3

User Guanhuiwit
by
5.0k points