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1 vote
Write the following expression as a single

logarithm with coefficient 1.
log3(6c) + log3 1/12

User Duston
by
4.7k points

2 Answers

3 votes

Answer: the answer is log3(c/2)

Explanation:

User Sandeep Panda
by
4.8k points
3 votes

Answer:

log3 {c/2}

Explanation:

Addiing two logs together is equivalent to multiplying their arguments.

Thus,

log3(6c) + log3 1/12 = log3 6*c*[1/12], or log3 ( log3 [6c][1/12] ).

This simplifies to log3 {c/2} because 6c(1/12) = c/2

User BrianC
by
4.9k points