Question

2. A circuit consists of a 10.0-ohm resistor,

a 15.0-ohm resistor, and a 20.0-ohm
resistor connected in parallel across a
9.00-volt battery. What is the equivalent
resistance of this circuit?
(1) 0.200 12 (3) 4.62 1
(2) 1.95.22
(4) 45.012

Answer 1

(3) 4.62 ohms

Step-by-step explanation:

Te equivalent resistance R is gotten from

1/R = 1/R₁ + 1/R₂ + 1/R₃ where R₁ = 10.0 ohm, R₂ = 15.0 ohm and R₃ = 20.0 ohm

1/R = 1/10 + 1/15 + 1/20

1/R = 0.1 + 0.0667 + 0.05

1/R = 0.2167

R = 1/0.2167

R = 4.62 ohms