Answer:
![(2)/(13)](https://img.qammunity.org/2021/formulas/mathematics/high-school/yc3cz9rrw4xb8gn0svc85pu9e3ynfl5kmo.png)
Explanation:
Our sample space is the total number of cards in a deck, n(S)=52
Event A: Event that she chooses a three card
Number of 3 cards in a deck, n(A)=4
Event B: Event that she chooses a seven card.
Number of 7 cards in a deck, n(B)=4
In Probability, P(A or B)=P(A)+P(B)
![P(A)=(n(A))/(n(S))= (4)/(52)= (1)/(13)\\P(B)=(n(B))/(n(S))= (4)/(52)= (1)/(13)\\P(A\: or \: B) = (1)/(13)+ (1)/(13)\\= (2)/(13)](https://img.qammunity.org/2021/formulas/mathematics/high-school/8bb4bkm7zobunj0c15wq7z9opept6trrxd.png)
The probability that Zhi Qing chooses is either a three or a seven is 2/13.