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The following question has two parts. First, answer Part A.

Then, answer Part B.
A number cube that has sides numbered 1 through 6 is rolled
180 times.
Part A
How many times would you expect the result to be an even number
greater than 2?
Write the answer in the box.
times
Part B
How many times would you expect the result to be a number less
than 6?
Write the answer in the box.
times​

User Karadous
by
4.9k points

1 Answer

4 votes

Part A:

To determine how many times we would expect the result to be an even number greater than 2, we need to calculate the probability of rolling an even number greater than 2 on a number cube.

There are three even numbers greater than 2 on a number cube, which are 4, 5, and 6. Out of the six possible outcomes (numbers 1 through 6), half of them are even numbers greater than 2.

Therefore, the probability of rolling an even number greater than 2 is 1/2.

To find the expected number of times, we multiply the probability by the total number of rolls:

Expected number of times = Probability * Total number of rolls

Expected number of times = (1/2) * 180

Expected number of times = 90

Therefore, we would expect the result to be an even number greater than 2 approximately 90 times.

Part B:

To determine how many times we would expect the result to be a number less than 6, we need to calculate the probability of rolling a number less than 6 on a number cube.

There are five numbers less than 6 on a number cube, which are 1, 2, 3, 4, and 5. Out of the six possible outcomes (numbers 1 through 6), five of them are less than 6.

Therefore, the probability of rolling a number less than 6 is 5/6.

To find the expected number of times, we multiply the probability by the total number of rolls:

Expected number of times = Probability * Total number of rolls

Expected number of times = (5/6) * 180

Expected number of times = 150

Therefore, we would expect the result to be a number less than 6 approximately 150 times.

User Steve Keenan
by
5.1k points