Question

10) What is the energy of a photon whose frequency is 2.7 X 1014 Hz?

A) 2.45x10-20)
B) 2.45x1048)
C) 17.9x10-20
D) 17.9x1048)

Answer 1

Answer: c

Step-by-step explanation:

`E=hf`

h = constant

f = frequency

`E=(6.626x10^-^3^4J/s)(2.7x10^1^4Hz)\\E=1.78902x 10^-^1^9`

moving the point 1 number to the right, and rounding up, leaves us with;

`E=17.9x 10^-^2^0`