Question

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What is the total surface area of the square pyramid? A square pyramid. The square base has side lengths of 8 inches. The triangular sides have a height of 5 inches. __________ square inches A.20 B.40 C.104 D.144

Answer 1

D. 144

Explanation:

4 triangles + square

4(½ × 8 × 5) + 8²

4(20) + 64

80 + 64

144 in²

Answer 2

D

Explanation:

The surface area of a square pyramid is simply the sum of the areas of the square base and the four congruent triangular sides.

The area of a square is: A = s * s, where s is the side length. Here, the side length is s = 8 in, so plug this in: A = 8 * 8 = 64 inches squared.

The area of a triangle is: A = (1/2) * b * h, where b is the base and h is the height. Here, the base is b = 8 and the height is h = 5. Plug these in:

A = (1/2) * 8 * 5 = 4 * 5 = 20 inches squared.

Since there are four triangles, multiply 20 by 4: 20 * 4 = 80 inches squared.

Add this to the area of the square:

80 + 64 = 144 inches squared

The answer is D.