Answer : The molarity of the resulting solution is, 0.29 M
Explanation :
When NaCl dissolved in water then it dissociates to give sodium ions and chloride ions.
Given,
Moles of
= 0.87 mol
Volume of solution = 3.00 L
Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.
Formula used :
![\text{Molarity}=\frac{\text{Moles of }NaCl}{\text{Volume of solution (in L)}}](https://img.qammunity.org/2021/formulas/chemistry/college/28arvgxv4hzwdgzwwyiw5yox6lkb79cerh.png)
Now put all the given values in this formula, we get:
![\text{Molarity}=(0.87mol)/(3.00L)=0.29mole/L=0.29M](https://img.qammunity.org/2021/formulas/chemistry/college/vdo14g1mzunighytl7q0f8kyjt9w0zhoc6.png)
Therefore, the molarity of the resulting solution is, 0.29 M