Question

Rafael spins the pointers of the two spinners shown at the right. Find the probability of each possible sum.

Answer 1

P(sum 2)=1/6

P(sum 3)=1/3

P(sum 4)=1/3

P(sum 5)=1/6

Explanation:

`\left|\begin{array}ccc&1&2&3\\---&---&---&----\\1&2&3&4\\2&3&4&5\end{array}\right|`

On the table, there are a a total of 6 outcomes.

• Number of sum that equals 2=1
• Number of sum that equals 3=2
• Number of sum that equals 4=2
• Number of sum that equals 5=1

Therefore:

P(sum 2)=1/6

P(sum 3)=2/6=1/3

P(sum 4)=2/6=1/3

P(sum 5)=1/6