Question

PLEASE SHOW STEPS!

You heat a 0.45 kg sample of metal to a temperature of
80 °C then quickly transfer it into a beaker that contains 0.70 kg of water at 15 °C; the specific heat capacity of water is 4 200 J/kg·°C. The highest temperature of the sample plus the water is 21 °C. What is the heat capacity of the sample of metal?

Answer 1

660 J/kg/°C

Step-by-step explanation:

Heat lost by metal = heat gained by water

-m₁C₁ΔT₁ = m₂C₂ΔT₂

-(0.45 kg) C₁ (21°C − 80°C) = (0.70 kg) (4200 J/kg/°C) (21°C − 15°C)

C₁ = 660 J/kg/°C