Question

What is the potential energy of an apple that has a mass of 0.12 kg being

held 0.8 meters above the ground?

Answer 1

`\displaystyle U_g = 0.9408 \ J`

General Formulas and Concepts:

Energy

Gravitational Potential Energy:
`\displaystyle U_g = mgh`

• m is mass (in kg)
• g is gravity (9.8 m/s²)
• h is height (in m)

Step-by-step explanation:

Step 1: Define

Identify variables

[Given] m = 0.12 kg

[Given] h = 0.8 m

[Solve] U

Step 2: Solve

1. Substitute in variables [Gravitational Potential Energy]:
   `\displaystyle U_g = (0.12 \ kg)(9.8 \ m/s^2)(0.8 \ m)`
2. Multiply:
   `\displaystyle U_g = (1.176 \ kg \cdot m/s^2)(0.8 \ m)`
3. Multiply:
   `\displaystyle U_g = 0.9408 \ J`

Topic: AP Physics 1 - Algebra Based

Unit: Energy

Book: College Physics