Question

Item 16

A dresser in the shape of a rectangular prism measures 2 feet by 2 feet by 6 feet. What is the surface area of the dresser?



square feet

Answer 1

Surface area of the dresser is 56ft²

Explanation:

Surface area of a rectangular prism is expressed as S = 2(LW+LH+WH)

L is the length the prism

W is the width

H is the height

If the rectangular prism measures 2 feet by 2 feet by 6 feet

L = 2feet, W = 2feet, height = 6feet

S = 2{(2)(2)+2(6)+2(6)}

S = 2{4+12+12}

S = 2×28

S = 56ft²

Answer 2

Explanation:

Given that the dresser is in shape of a rectangular prism

Note that, a rectangular prism has a shape of a cuboid

So, area of the rectangular prism is same as area of a cuboid

A = (2LB + 2LH + 2BH)

Where

L is length

B is breadth

H is height

Then, given the dimension of the rectangular prism to be

2ft by 2ft by 6ft

Then, you can assume that,

Length L = 2ft

Breadth B = 2ft

Height H = 6ft.

NOTE: you can take you assumption anyhow, there is no standard, you will get the same answer.

Then,

A = (2LB + 2LH + 2BH)

A = (2×2×2 + 2×2×6 + 2×2×6)

A = (8 + 24 + 24)

A = 56 ft²

The total surface area of the dresser is 56ft²