Question

In a basketball tournament, Team A scored 5 less than twice as many points as Team B. Team C scored 80 more points than Team B. The combined score for all three teams was 983 points. Let the variable b represent Team B's total points. The equation representing this scenario is (2b – 5) + b + (b + 80) = 983. Team B scored 227 total points.

Answer 1

c

Explanation:

Answer 2

Team B scored 227 points.

Explanation:

The expression that models this problem is

`(2b-5)+b+(b+80)=983`

To know the total points Team B scored, we just need to solve the expression for
`b`

`2b-5+b+b+80=983\\4b=983-80+5\\4b=908\\b=(908)/(4) \\b=227`

Therefore, Team B scored 227 points.

Notice that the problem specifies each term of the expression.

"Team A scored 5 less than twice as many points as Team B":
`2b-5`

"Team C scored 80 more points than Team B":
`b+80`

"They combined score was 983 points": = 983.

With all this information, we defined the expression to find
`b`