Question

Particle q1 has a positive 6 µC charge. Particle q2 has a positive 2 µC charge. They are located 0.1 meters apart.

Recall that k = 8.99 × 109 N•meters squared per Coulomb squared.


What is the force applied between q1 and q2?

Answer 1

10.8 N

Step-by-step explanation:

Answer 2

F = 10.788 N

Step-by-step explanation:

Given that,

Charge 1,
`q_1=6\ \mu C=6* 10^(-6)\ C`

Charge 2,
`q_2=2\ \mu C=2* 10^(-6)\ C`

Distance between charges, d = 0.1 m

We know that there is a force between charges. It is called electrostatic force. It is given by :

`F=(kq_1q_2)/(d^2 )\\\\F=(8.99* 10^9* 6* 10^(-6)* 2* 10^(-6))/((0.1)^2 )\\\\F=10.788\ N`

So, the force applied between charges is 10.788 N.