Answer:
See below
Explanation:
I assume you want the quadratic that has these values
Vertex form of this parabola
y = a(x- - 1)^2 + 4 insert the given point to calculate 'a'
8 = a (1 + 1)^2 + 4 shows a = 1
y = (x+1)^2 + 4 expand this vertex form to get the quadratic form
y = x^2 + 2x + 5