Question

Alex and Josh rode bikes. Alex rode 15 miles in 55 minutes. Josh rode 77 minutes at a faster rate per mile than Alex. Find Alex's unit rate in minutes per mile. What is Josh's rate per mile?

Answer 1

a)
`x = (11)/(3)\,(min)/(mi)`, b)
`y = (77)/(15)\,(min)/(mi)`

Explanation:

a) The indicator is equal to the ratio of total time to travelled distance:

Alex

`x = (55\,min)/(15\,mi)`

`x = (11)/(3)\,(min)/(mi)`

b) In the case of Josh, the ratio must be greater than x. Then:

`y = (77\,min)/(15\,mi)`

`y = (77)/(15)\,(min)/(mi)`