Question

A 3.0- resistor is connected in parallel with a 6.0- resistor. This combination is connected in series with a 4.0- resistor. The resistors are connected to a 12-volt battery. How much power is dissipated in the 3.0- resistor

Answer 1

5.33 w

Step-by-step explanation:

parallel resistors equivalent r = r1 r2 /(r1+r2) = 2 ohm

in series with 4 ohm resistor makes total r = 6 ohms

12 v / 6 ohm = 2 amps current

2/3 of the current will go through the 3 resistor

2/3 * 2 = 4/3 amp

power = I^2 R = 4/3 ^2 * 3 = 5.33 watts