What mass of CO2 will sublimate given 500 kJ of energy at room temperature? (ΔHsub=26.1kJmole)

asked Jul 10, 2021 217k views

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1 vote

Answer:

843 g

Step-by-step explanation:

500 kJ(1 mole26.1 kJ)(44.0 g1 mole)=843 g

Elliott Hill answered Jul 14, 2021

7.6k points

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