Question

3 people traveled 27 miles total and person number 2 went 6 miles more than person number 1 and person number 3 went 3 miles more than person number 2. Solve problem algebraically

Answer 1

3 miles,9 miles and 15 miles

Explanation:

GIVEN:
`3` people traveled
`27` miles total and person number
`2` went
`6` miles more than person number
`1` and person number
`3` went
`3` miles more than person number
`2`.

TO FIND: Solve problem algebraically.

SOLUTION:

Let the distance traveled by person
`1` be
`x`

distance traveled by person
`2`
`=x+6`

distance traveled by person
`3=2x+9`

According to the question

Total distance traveled by all
`=27`

`x+x+6+2x+9=27\implies4x+15=27`

`\implies 4x=12`

`\therefore x=3`

first person traveled
`=3\text{ miles}`

Second person traveled
`=x+6=9\text{ miles}`

Third person traveled
`=2x+9=15\text{ miles}`

Hence person number 1,2 and 3 traveled 3 miles,9 miles and 15 miles respectively.

Answer 2

Answer : The distance travelled by person 1, person 2 and person 3 is, 4 miles, 10 miles and 13 miles respectively.

Step-by-step explanation :

Let the distance travelled by person number 1 = x miles

Then, the distance travelled by person number 2 = (x+6) miles

And, the distance travelled by person number 3 = (x+6) + 3 miles = (x+9) miles

Total distance travelled by 3 persons = 27 miles

As per question,

x + (x+6) + (x+9) = 27

3x + 15 = 27

3x = 27 - 15

3x = 12

x = 4

The distance travelled by person number 1 = x miles = 4 miles

The distance travelled by person number 2 = (x+6) miles = (4+6) miles = 10 miles

The distance travelled by person number 3 = (x+9) miles = (4+9) miles = 13 miles