Answer:
θ = 27.47°
Explanation:
This problem can be represented as a right-angled triangle, as shown in the diagram below.
To find θ, we apply the tangent part of the trigonometric ratios SOHCAHTOA:
tanθ =
![(opposite)/(adjacent)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/yrlrkg5107bgx4j2edwa224fmqqlf2z6tm.png)
In the diagram, opposite = 1.3 m and adjacent = 2.5 m
Hence:
tanθ =
![(1.3)/(2.5)](https://img.qammunity.org/2021/formulas/mathematics/high-school/ezrto3n64ii75ut8o2qykij3s9rqrmwzb0.png)
tanθ = 0.52
θ =
![tan^(-1) 0.52](https://img.qammunity.org/2021/formulas/mathematics/high-school/he2x0s1l79djtm0lsrlb8tdf831y1r4rbw.png)
θ = 27.47°
The ramp forms 27.47° with the ground.