Question

(5 points) In the lab you find four bags; each contains 5.00 g of a different gas at STP. The gases are O2, C2H6, CO2, and Ne. Which bag has the largest volume?

Answer 1

Ne

Step-by-step explanation:

Step 1:

Data obtained from the question. This includes:

Mass of O2 = 5g

Mass of C2H6 = 5g

Mass of CO2 = 5g

Mass of Ne = 5g

Step 2:

Determination of the number of mole of each gas:

For O2:

Mass of O2 = 5g

Molar Mass of O2 = 16x2 = 32g/mol

Number of mole of O2 =?

Number of mole = Mass/Molar Mass

Number of mole of O2 = 5/32

Number of mole of O2 = 0.156 mole

For C2H6:

Mass of C2H6 = 5g

Molar Mass of C2H6 = (12x2) + (6x1) = 24 + 6 = 30g/mol

Number of mole of C2H6 =?

Number of mole = Mass/Molar Mass

Number of mole of C2H6 = 5/30

Number of mole of C2H6 = 0.167 mole

For CO2:

Mass of CO2 = 5g

Molar Mass of CO2 = 12 + 16x2 = 12 + 32 = 44g/mol

Number of mole of CO2 =?

Number of mole = Mass/Molar Mass

Number of mole of CO2 = 5/44

Number of mole of CO2 = 0.114 mole

For Ne:

Mass of Ne = 5g

Molar Mass of Ne = 20g/mol

Number of mole of Ne =?

Number of mole = Mass/Molar Mass

Number of mole of Ne = 5/20

Number of mole of Ne = 0.25 mole

Step 3:

Determination of the volume occupied by the each gas.

1 mole of a gas occupy 22.4L at stp.

For O2:

0.156 mole will occupy = 0.156 x 22.4 = 3.49 L

For C2H6:

0.167 mole Will occupy = 0.167 x 22.4 = 3.74 L

For CO2:

0.114 mole Will occupy = 0.114 x 22.4 = 2.55 L

For Ne:

0.25 mole will occupy = 0.25 x 22.4 = 5.6 L

From the calculations made above, Ne has the largest volume