Answer:
a) p = 0.625
b) (0.563, 0.687)
c) This means that we are 99% sure that the true proportion of all viewers who would prefer the comedy show over the crime investigation show is between (0.563, 0.687).
Explanation:
a. Estimate the value of the population proportion.
Sample: 250 viewers would prefer the comedy show over the crime investigation show, out of 400 viewers sampled. So
b. Develop a 99 percent confidence interval for the population proportion.
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of
.
For this problem, we have that:
99% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:
The upper limit of this interval is:
c. Interpret your findings.
This means that we are 99% sure that the true proportion of all viewers who would prefer the comedy show over the crime investigation show is between (0.563, 0.687).