Question

How many milliliters of 0.0896M LiOH are required to titrate 25.0 mL of 0.0759M HBr to the equivalence point?

Answer 1

`V_(LiOH)=21.8mL`

Step-by-step explanation:

Hello,

In this case, during titration at the equivalence point, we find that the moles of the base equals the moles of the acid:

`n_(LiOH)=n_(HBr)`

That it terms of molarities and volumes we have:

`M_(LiOH)V_(LiOH)=M_(HBr)V_(HBr)`

Next, solving for the volume of lithium hydroxide we obtain:

`V_(LiOH)=(M_(HBr)V_(HBr))/(M_(LiOH)) =(0.0759M*25.0mL)/(0.0896M) \\\\V_(LiOH)=21.8mL`

Best regards.