Question

The combustion reaction of isopropyl alcohol is given below: C 3 H 7 O H ( l ) + 9 2 O 2 ( g ) → 3 C O 2 ( g ) + 4 H 2 O ( g ) The heat of combustion of isopropyl alcohol is -2006 kJ/mol. Given the following information, calculate the heat of formation of isopropyl alcohol.

Answer 1

The heat of formation of isopropyl alcohol can be calculated using the heat of combustion and the stoichiometry of the reaction.

Step-by-step explanation:

The heat of combustion of isopropyl alcohol, C3H7OH, is given as -2006 kJ/mol. We can use this information to calculate the heat of formation of isopropyl alcohol.

The heat of formation of a compound is defined as the heat released or absorbed when one mole of the compound is formed from its constituent elements in their standard states.

The balanced equation for the combustion of isopropyl alcohol is:

C3H7OH (l) + 9/2 O2 (g) → 3 CO2 (g) + 4 H2O (g)

From the balanced equation, we can see that 3 moles of CO2 and 4 moles of H2O are formed for every mole of isopropyl alcohol combusted.

Using the given heat of combustion and the stoichiometry of the reaction, we can calculate the heat of formation of isopropyl alcohol using the equation:

Heat of formation of isopropyl alcohol = [3 mol CO2 × (-2006 kJ/mol)] / 1 mol isopropyl alcohol