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Last year your professor wanted to study the pattern in class grades. The following table contains a sample of grades collected from the final exam last semester:

64 80 75 98 75

Using Table and looking at the relative positions of the Mean, Median and Mode for the sample, what can you say about the distribution?

User Barneytron
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Answer:

mean = 78.4

median = 77.5

mode = 75

This is Right - skewed (positive skewness) distribution

Explanation:

Mean:-

The mean (average) is found by adding all of the numbers together and dividing by the number of items and it is denoted by x⁻

mean =
(64+80+75+98+75)/(5)

mean (x⁻ ) = 78.4

The mean of the given data = 78.4

Median:

The median is found by ordering the set from lowest to highest and finding the exact middle.

64 ,75, 80, 98

The middle term of the given data set =
(75+80)/(2) =77.5

Mode :

The mode is the most common repeated number in a data set.

64 ,75, 75, 80, 98

in data the most common number = 75

Conclusion:-

mean = 78.4

median = 77.5

mode = 75

This is Right - skewed (positive skewness) distribution

Last year your professor wanted to study the pattern in class grades. The following-example-1
User Razmig
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