Question

A proton moves eastward in the plane of Earth's magnetic field so that the distance from the ground remains constant. What speed is the speed of the proton if Earth's magnetic field points north and has a magnitude of 5.0 x 10-5 T?

Answer 1

Speed is 1.962*10^-3m/s

Step-by-step explanation:

Given that

Mass of proton==1.67*10^-27

Acceleration due to gravity (g)=9.81m/s^2

Angle of inclination A=90°

Charge (q)=1.6*10^-19

Magnetic field (B)=5*10^-5T

From lorentz force

It can be seen that

F=w =mg=qvBsinA

We're Velocity (v)=mg /qBsinA

V=1.67*10-27*9.81/1.6*10^-19*5*10^-5*sin90

V=1.962*10^-3m/s