Answer: T = -0.213°c
Heat flow = 38.2 w/m²
Explanation:
given data:
Wood = 0.031m thick
Styrofoam = 0.023m thick
Wood = k ( 0.080W/m.k)
Styrofoam = k (0.010W/m.k)
Temperature of wood = -15°c
Temperature of styrofoam = 19°c
(a) heat flow in wood and styrofoam must be equal
KAdT/ L = KAdT/ L
0.080 * A * ( T - ( -15) ) / 0.031 = 0.010 * A * ( T - ( 19°c) ) / 0.023
T = -0.213°c
(b) heat flow
H = KAdT / L
H = 0.080 * A * ( -0.213°c - ( -15°c) ) / 0.031
= 38.2 w/m²