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Help me find Angle BAD

Help me find Angle BAD-example-1

2 Answers

5 votes

We have parallelogram ABCD and isosceles triangle ADE, with equal angles ∠ADE = ∠AED.

∠ADE + ∠AED + ∠EAD = 180°

2 ∠ADE + 52° = 180°

∠ADE = (180° -52°) / 2 = 64°

∠ADE and ∠BAD are alternate interior angles of a transversal through parallel lines, so they're congruent. So ∠BAD is

Answer: 64°

User Krakover
by
7.8k points
4 votes

Answer:

BAD = 64°

Explanation:

ADE = (180-52):2 = 64°

ED || AB => ADE = BAD = 64°

User Martin Blore
by
7.8k points

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