Question

what is the new pressure acting on a 2.5 l balloon if its original volume was 5.8 l at 3.7 ATM of pressure

Answer 1

Answer : The new pressure acting on a 2.5 L balloon is, 8.6 atm.

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

`P\propto (1)/(V)`

or,

`P_1V_1=P_2V_2`

where,

`P_1` = initial pressure = 3.7 atm

`P_2` = final pressure = ?

`V_1` = initial volume = 5.8 L

`V_2` = final volume = 2.5 L

Now put all the given values in the above equation, we get:

`3.7atm* 5.8L=P_2* 2.5L`

`P_2=8.6atm`

Thus, the new pressure acting on a 2.5 L balloon is, 8.6 atm.