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Expand the logarithmic expression log3(2xy3z5). Question 9 options: A) 2(log3x + 3log3y + 5log3z) B) log32x + log3y3 + log3z5 C) log32 + log3x + 3log3y − 5log3z D) log32 + log3x + 3log3y + 5log3z

User Huusom
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Answer: D

Explanation:


\log _(3)\left(2 x y^(3) z^(5)\right) \\ =\log _(3) 2+\log _(3) x+\log _(3) y^(3)+\log _(3) z^(5)


\left(\because \log _(c)(a \cdot b)=\log _(c) a+\log _(c) b\right)


=\log _(3) 2+\log _(3) x+3 \log _(3) y+5 \log _(3)z \rightarrow \left(\because \log _(c) a^(b)=b \log _(c) a\right)

Therefore, Option D is the correct answer

User Ytyng
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