Answer:
we know
X = -b±(√b^2-4ac)
_____________
2a
NOW COMPARING X^2-5X-2=0 WITH AX^2+BX+C=0
WE GET
A=1
B=-5
C=-2
AGAIN,
X=-(-5)±√(-5)^2-4×1×(-2)
___________________
2×1
TAKING POSITIVE and negative you can find out answer
2e3l2m/ r=3
Explanation:
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