Question

Use the quadratic formula to solve x^2-5x-2=0

Answer 1

we know

X = -b±(√b^2-4ac)

_____________

2a

NOW COMPARING X^2-5X-2=0 WITH AX^2+BX+C=0

WE GET

A=1

B=-5

C=-2

AGAIN,

X=-(-5)±√(-5)^2-4×1×(-2)

___________________

2×1

TAKING POSITIVE and negative you can find out answer

Answer 2

2e3l2m/ r=3

Explanation: