Question

Can someone solve this?

Answer 1

Considering the Law of Cosines:

`c^2=a^2+b^2-2ab*cosC`

`a=14mi; b=24mi; c=CA; C=91degrees`

`\cos \left(91^(\circ \:)\right)=-0.01745\dots`

`c^2=14^2+24^2-2(14)(24)*\cos \left(91^(\circ \:)\right)\\c^2=196+576-672*\cos \left(91^(\circ \:)\right)\\c^2=772-672*\cos \left(91^(\circ \:)\right)\\c^2=772-672*(-0.01745)\\c^2=772+11.7264\\c=√(772+11.7264) \\c=√(783.7264)\\c=27.99mi`