132.67 K is the temperature at which 55 grams of chlorine gas exert a pressure of 245 kPa at a volume of 3.4 liter.
Step-by-step explanation:
Data given:
mass of chlorine gas = 55 grams
atomic mass of chlorine gas = 71 grams/mole
pressure of chlorine gas = 245 kPa 0R 2.41 atm
volume of the chlorine gas = 3.4 litres
temperature of the chlorine gas = ?
R = 0.08201 Latm/moles K
n =?
Assuming that chlorine behaved like ideal gas, the formula used will be,
PV = nRT
number of moles =
![(mass)/(atomic mass of 1 mole)](https://img.qammunity.org/2021/formulas/chemistry/middle-school/etdel16ed6rk1gzvpxl9k8xjq0wos1bgnw.png)
number of moles=
![(55)/(71)](https://img.qammunity.org/2021/formulas/chemistry/college/912izs3hdqkmb28fq3koo0682izcycbtp8.png)
number of moles = 0.77
putting the values in ideal gas equation:
T =
![(2.41 X 3.4)/(0.08021 X 0.77)](https://img.qammunity.org/2021/formulas/chemistry/college/da79j8d1mnq7uv1aob4tr2y6onkmuipcgp.png)
T = 132.67 K
temperature is 132.67 K