Question

1. As a particle moves 12m along an electric field of strength 76N/C, its electrical potential energy decreases by 4.9 * 10 ^ - 16 * J . What is the particle's charge?

Answer 1

Charge,
`q=5.37* 10^(-19)\ C`

Step-by-step explanation:

Given that,

Distance moved by particle, d = 12 m

Electric field strength, E = 76 N/C

Decrease in potential energy,
`P=4.9* 10^(-16)\ J`

We need to fine the charge on the particle. The change in potential energy of the system is given by :

`P=qEd`

q is charge

`q=(P)/(Ed)\\\\q=(4.9* 10^(-16))/(76* 12)\\\\q=5.37* 10^(-19)\ C`

So, the charge on the particle is
`5.37* 10^(-19)\ C`.