Answer:
(x−1)43x3−8x2+10 can be resolved into partial fraction as x−1A+(x−1)2B+(x−1)3C+(x−1)4D
So , 3x3−8x2+10=A(x−1)3+B(x−1)2+C(x−1)+D
Put x=1 , we get 3−8+10=D
D=5
Comparing the coefficient of x3 on both sides we get , A=3 .
So equation reduces to 3x3−8x2+10=3(x−1)3+B(x−1)2+C(x−1)+5
Now compare the constant on both sides , 10=−3+B−C+5
=>8=B−C - (1)
Comparing the coefficent of x2 we get −8=−9+B
=>B=1
So , put B=1 in (1) , we get C=−7
Therefore , (x−1)43x3−8x2+10=x−13+(x−1)21−(x−1)37+(x−1)45
Explanation:
hope it helps